Math, asked by nehasreekumar2002, 6 months ago

what is the probability of getting one sunday in a non leap year?

Answers

Answered by Anonymous

Answer:

In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday, Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays would be 1/7.

Answered by diya0007sharma

Answer:

Explanation

In 365 days, Number of weeks = 52 weeks and 1 day is remaining. 1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 /7

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