Question

what is the probability of getting the number multiple of 6 or 7 from first 200 natural number​

Answer 1

Answer:

P(multiple of 6) = 33

200

P( multiple of 7) = 28

200

Explanation

P(6) = Total no. of multiple of 6 till 200

Total no. of outcomes

finding the last multiple of 6 till counting 200

200÷6

Q= 33

R= 2

So, the no. 200-2 is divisible by 6 = 198 at the no. 33.

Hence, P(6) = 33

200

P(7) = Total no. of multiple of 7 till counting 200

Total no. of outcomes

finding the last multiple of 6 till counting 200

200÷7

Q= 28

R= 4

So, the no. 200-4 is divisible by 7 = 196 at the no. 28.

Hence, P(6) = 28

200

Thank you :)