what is the probability of having 53 sunday in a non leap year?
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in a non leap year there are 365 days. so there are 52 weeks.
then,52× 7 =364
=> 1 day is remaining so which can be any day of the week.
so the probability of getting 53 Sundays=1/7
hope this is correct and helps you..
then,52× 7 =364
=> 1 day is remaining so which can be any day of the week.
so the probability of getting 53 Sundays=1/7
hope this is correct and helps you..
vandanaparisharma:
ya
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