what is the probability of having 53 Sunday in a non leap year??
sagar1031:
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HEY MATE,
UR ANSWER
favourable outcomes=1
total otcomes=7
probability =1/7....
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Answered by
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no. of days in leap year = 365
no. of weeks =366/7= 52weeks + 1days
sample space for 1 days= (S,M,T,W,T,F,SA)
Ns = 7
let event A be one of that is sunday
NA = 1
PA= 1/7
Please mark me brainiest
no. of weeks =366/7= 52weeks + 1days
sample space for 1 days= (S,M,T,W,T,F,SA)
Ns = 7
let event A be one of that is sunday
NA = 1
PA= 1/7
Please mark me brainiest
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