Question

what is the probability of having 53 Sundays in a leap year​

Answer 1

Answer:

2 by 7 is the probability

and in normal year probability is 1 by 7

Answer 2

Answer:

The possible pairs are ( Saturday, Sunday) and (Sunday, Monday), So n(E) =2. Therefore theprobability of a leap year having 53 Sundays = n(E)/n(S) = 2/7.

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