What is the probability of having 53 Sundays in a leap year and non-leap year.
drushasangwan:
1/7 and 2/7
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For solving this question we should know a basic fact about a year i.e. it has 52 weeks.
52 weeks means 52×7 = 364 days.
If the year in an ordinary year, the one odd day could be Monday,Tuesday, Wednesday…… Sunday. Thus the probability of getting a sunday is 1/7.
If the year is a leap year, the two odd days could be
Mon Tue, Tue Wed, Wed Thu , Thu Fri , Fri Sat , Sat Sun , Sun Mon.
Thus the probability of getting a sunday is 2/7
Hope this Helps !!
For solving this question we should know a basic fact about a year i.e. it has 52 weeks.
52 weeks means 52×7 = 364 days.
If the year in an ordinary year, the one odd day could be Monday,Tuesday, Wednesday…… Sunday. Thus the probability of getting a sunday is 1/7.
If the year is a leap year, the two odd days could be
Mon Tue, Tue Wed, Wed Thu , Thu Fri , Fri Sat , Sat Sun , Sun Mon.
Thus the probability of getting a sunday is 2/7
Hope this Helps !!
A better answer will be satisfactory.
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answer is in pic ok
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