What is the probability of having 53 sundays in a non leap year?
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Answered by
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The probability is 2/7.
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Answered by
1
Answer:
Step-by-step explanation:
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 sundays = 1 / 7.
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