What is the probability of having at least one 'six' from 3 throws of a perfect die?
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what is the probability of having at least one 6 from three throws of a perfect die? The probability of getting 6 for single through is 1/6. for three throw it will be 3*1/6 = 1/2.
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No of possible events =1
Total possibilities. = 6
Probability of getting
1 = 3(1/6)=1/2
Total possibilities. = 6
Probability of getting
1 = 3(1/6)=1/2
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