What is the probability of having getting53 fridays in a leap year?
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A year has 52 weeks
52*7=364 days
a leap year has 366 days.
the possible combinations of remaining 2 days are
SM, MT, TW, WT, TF, FS, SS = 7
combinations with friday = TF, FS = 2
thus probabiloty of getting 53 fridays =
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