Math, asked by Tanyav4366, 1 year ago

What is the probability of having getting53 fridays in a leap year?

Answers

Answered by sarankumarmec

0

A year has 52 weeks

52*7=364 days

a leap year has 366 days.

the possible combinations of remaining 2 days are

SM, MT, TW, WT, TF, FS, SS = 7

combinations with friday = TF, FS = 2

thus probabiloty of getting 53 fridays = $\frac{2}{7}$

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