what is the probability of non leap year seleted at random will contain 53 sundays?
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1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.
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1/7 is your answer bro, hope it helped you please thank the answer and mark this answer as brainiest answer if you understood
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