Question

what is the probability of not getting 53 sundays in a leap year​

Answer 1

Answer:

The answer is 2.

Step-by-step explanation:

In 365 days, Number of weeks = 52 weeks and 1 day is remaining. 1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.

Answer 2

Answer:

5/7

Step-by-step explanation:

No. of days in leap years = 366 = 52 weeks + 2 days.

Now, these 2 days can be any of the gollowing pairs :-

(Mon. & Tues), (Tues. & Wed.), (Wed. & Thurs.), (Thurs. & Fri.), (Fri. & Sat.), (Sat. & Sun.) & (Sun. & Mon.)

No. of Total Observations = 7

No. of Favourable Observations = 5

Required Probability = 5/7