What
is
the
probability of picking
a number at random
from
100 to
999
such
that
the
number's middle
digit is sum of the
digits on either side?
Answers
Answered by
1
Answer:
0.045
Step-by-step explanation:
For middle number to be sum of either end digits
let the number be abc
let's consider cases
i)b=1
a=1 c= 0 no of cases =1
ii)b=2
a 1 c 1
a 2 c 0 no of cases =2
iii)b=3
a 1 c 2
a 2 c 1
a 3 c 0 no.of cases = 3
so it has a pattern no.of cases = value of b
therefore total no.of cases = 1+2+3+4+5+6+7+8+9=45 cases
probability= 45/1000= 0.045
Answered by
0
Answer:
the above answer is right
Step-by-step explanation:
hope it's help you
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