Question

What
is
the
probability of picking
a number at random
from
100 to
999
such
that
the
number's middle
digit is sum of the
digits on either side?​

Answer 1

Answer:

0.045

Step-by-step explanation:

For middle number to be sum of either end digits

let the number be abc

let's consider cases

i)b=1

a=1 c= 0 no of cases =1

ii)b=2

a 1 c 1

a 2 c 0 no of cases =2

iii)b=3

a 1 c 2

a 2 c 1

a 3 c 0 no.of cases = 3

so it has a pattern no.of cases = value of b

therefore total no.of cases = 1+2+3+4+5+6+7+8+9=45 cases

probability= 45/1000= 0.045

Answer 2

Answer:

the above answer is right

Step-by-step explanation:

hope it's help you