Question

what is the probability of prime numbers in a die

Answer 1

total no. of outcomes = 6

possible outcomes = 3 (2,3,5)

probability = no of desired outcomes/total outcomes

= 3/6=1/2

hope this helps

Answer 2

Answer:

$here \: is \: ur \: answer$

Explanation:

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100}

n(S) = 100

A = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}

n(A) = 25

P(A) = n(A)/n(s)

= 25/100

=1/4

Ans :- The probability of the prime numbers from 1 to 100 is 1/4.