Question

What is the probability of the numbers is selected from 1 to 25 is a prime number ,when each of the given number is equally likely to be selected

Answer 1

$\text{Here is the answer}$

Prime Numbers from 1 to 25
=> {2, 3,5, 7, 11, 13, 17, 19, 23}

Thus,
X = {2, 3,5, 7, 11, 13, 17, 19, 23}

n[X] = 9

n[S] = 25

Thus,
Required Probability =

$\bf{\frac{n(X)}{n (S) } = \frac{9}{25} }$

Thus, the required probability is 9/25.

Final answer is
The probability of the numbers is selected from 1 to 25 is a prime number ,when each of the given number is equally likely to be selected is 9/25.

Thanks!!

Answer 2

$\textbf{\huge{ANSWER:}}$

Numbers from 1 to 25 = 25

Prime Numbers from 1 to 25 = 9

{2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23}

Probablity:

$\frac{Number \: of \: times \: the \: event \: occured}{Number \: of \: total \: events}$

Putting the respective values in this formula, we get:

$\frac{9}{25}$

As this fraction can be further simplified, this is the answer.

Hope it Helps!! :)

Feel free to ask if any doubts occur!