Question

What is the probability of winning the game ,if the probability of loosing the game is 0.029?

Answer 1

Answer:

0.971

Step-by-step explanation:

The probability of losing the game=0.029

then the probability of winning the game:

= P( not E)= 1- P(E)

where' not E'=probability  of contrary(opposite) to the event i.e probability of winning the game.)

where'E'=probability of the event to take (which in this question: it will be the probability of losing the game ( event)) = 0.029(given).

Therefore,

= P( not E)= 1- P(E)

=P(not E) = 1- 0.029

=P(not E)=0.971

so your answer will be 0.971 (which is the probability of winning the game)

Hope it helps you :-))