What is the probability of year 1991 having 53 Sundays?
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The probability of the year 1991 having 53 Sundays is 2 / 7
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Therefore the probability of a year having 53 Sundays = n(E)/n(S) = 1/7. If the year in question is a leap year, there are 366 days. Since 364 is a multiple of 7, there will be 52 Sundays, 52 Mondays,…………….53 Saturdays.
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