Question

what is the probability taht a number chosen from first 100 natural numbers is divisible by both 5 and 3​

Answer 1

First, Let us find the numbers which are divisible by 5 and 3, and are between 1 and 100.

Any number which divisible by both 3 and 5, would also be divisible by 15.

15, 30, 45, 60, 75, 90

As there are only 6 numbers so the number of favourable outcomes is 6, but there are 100 numbers so the number of possible outcomes is 100.

We know,

⇒ Probability = Number of Favourable outcomes / Number of possible outcomes

⇒ Probability = 6 / 100

⇒ Probability = 3/50

Hence, The probability of finding a number from 1 to 100 which is divisible by 3 and 5 is 3/50.

Some Information :-

▪ Probability of an event is the chance of occurrence of that event.

• Probability of an event can't be negative.
• Probability of an event can be 0. which is also known as Impossible event.
• Probability of an event can also be 1. So, It is known as True event.

Answer 2

Answer:

As there are only 6 numbers so the number of favourable outcomes is 6, but there are 100 numbers so the number of possible outcomes is 100. Hence, The probability of finding a number from 1 to 100 which is divisible by 3 and 5 is 3/50.