Question

What is the probability that a 2 digit number is a multiple of 3​

Answer 1

Answer:

(a) 2 digit positive integers which are multiples of 3 are 12, 15, 18, ... , 99. Thus, there are 30 such integers. (b) 2-digit positive integers are 10, 11, 12, ... , 99. Thus, there are 90 such numbers. Since out of these, 30 numbers are multiple of 3, therefore, the probability that a randomly chosen positive 2-digit integer is a multiple of 3, is 30/90 = 1/3.

I don't know whether it's right or wrong

Answer 2

Answer:

30/90=1/3

Step-by-step explanation:

here in the question they asked the two digit no. that can be the multiple of 3

i.e,12,15,18.....99 there r 30, 2digit multiples of 3

listen 99 is the last multiple of 3

99/3=33(includes single and double digit)

so 33-3

subtracting 3 because (3,6,9)also multiples of three but single digit

so,No. favorable income is =30

Total no. of incomes are 91 (99-9)

therefor probability is 30/90