Question

What is the probability that a leap year has 53 Sundays ?



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Answer 1

Answer:

hello here is your answer hope it helps u

Step-by-step explanation:

The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is72.

Answer 2

Answer:

we know that in normal year has 365 days with 7 day comprises a week.

Thus, number of weeks in normal year

= 365 ÷ 7 = 52 weeks and 1 left a day ( which is 52 Mondays ,52 Tuesdays ,52 wednesdays ,52 Thursday, 52 Fridays ,52 Saturdays ,52 Sundays ) .

A leap year has 366 days in which 2 days are left with 52 weeks.

That can be any of the day of a week.

so total possible days are :

( Sunday ,Monday); ( Monday ,Tuesday); ( Tuesday, Wednesday ); ( Wednesday, Thursday); ( Thursday, Friday); ( Friday ,Saturday); ( Saturday, Sunday);

so here favourable outcome = 2 ( i.e; (Sunday, Monday)

(Saturday, Sunday).

Total possible outcome =

Thus ,required for probability = 2/7.

Hence , the answer is 72.

I hope its help you.