Question

What is the probability that a leap year has 53 sundays and 52 mondays?

Answer 1

Answer:

A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.

hope it helps u

Answer 2

Answer:

Step-by-step explanation:

An leap year has 366 days.

i.e 52 weeks and 2 extra days.

52 weeks will have 52 mondays.

The sample space for two extra days is

S={sunday-monday,monday-tuesday,tuesday-wednesday,wednesday-thursday,thursday-friday,friday-saturday}

therefore n(S)=7

let A be the event of getting 53rd sunday in remaining 2 days.

A={saturday-sunday,sunday-monday}

therefore n(A)=2

P(A)=n(A)/n(S) = 2/7

The probability that a leap year has 53 sundays and mondays is 2/7.