What is the probability that a leap year has 53 Tuesdays and 53 Mondays?
Answers
Answer:
A leap year will have 53 Tuesdays and 53 Mondays if and only if January 1st is a Monnday. So the probability is close to 1/7. Meaning without leaving non leap years the probability will reach 1/28
years. So concluding, if there are 7 leap years one leap year will have such. For example:- 1996 had 53 Tuesdays and 53 Mondays do next such event will be in 2024, means a lapse of 28 years or rather 7 leap years. And next such event after 2024 will be in 2052.
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Answer:
Step-by-step explanation:
leap year has 366 days
therefore:
Leap year has 52 weeks and 2 days extra
so, IN 52 WEEKS THERE WILL BE 52 tuesdayes and 52 mondays
so, there are extra 2 days
therefore ;
N(S) = (sunday,monday),(monday,tuesday),(tuesday,wednesday),
(wednesday,thursday),(thursday,friday),(friday,saturday)
,(saturday,sunday)
N(S)= 7
so, let A be event of getting 53 tuesdays (in N(S) see which has one tuesday take it )
therefore;
N(A)=(monday,tuesday),(tuesday,wednesday)
N(A)= 2
P(A) = N(A)/N(S)
P(A)= 2/7
NEXT,
Let b be the event of getting 53 mondays, (in N(S) see which has one monday and take it)
therefore,
N(B)= (sunday,monday),(monday,tuesday)
N(B)= 2
THEREFORE,
P(B)= N(B)/N(S)