Question

What is the probability that a leap year has 53 Tuesdays or 53 Mondays ?​

Answer 1

Step-by-step explanation:

A leap year has 366 days.

Now 364 is divisible by 7 and therefore there will be two excess weekdays in a leap year.

The two excess weekdays can be

(Sunday, Monday),

(Monday, Tuesday),

(Tuesday, Wednesday),

(Wednesday, Thursday),

(Thursday, Friday),

(Friday, Saturday),

(Saturday, Sunday).

So, the sample space S has 7 pairs of excess weekdays. i.e. n(S)=7

Now we want the desired event E to have 53 Mondays and 53 Tuesdays.

E consists of only one pair in S which is (Monday, Tuesday).

So, n(E)=1

Hence, the probability that a leap year will contain 53 Mondays and 53 Tuesdays = n(E) = 1

n(S) 7

Source : https://www.toppr.com/ask/question/what-is-the-probability-that-a-leap-year-has-53/