what is the probability that a leap year, selected at random will contain 53 thrusday ?
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Hey... I think this can be ur answer dear!!
A leap year has 52 weeks and 2 days...
These 2 days can be:-
1) Sunday and Monday
2)Monday and Tuesday
3)Tuesday and Wednesday
4)Wednesday and Thursday
5)Thursday and Friday
6)Friday and Saturday
7)Saturday and Sunday
Therefore, n(S) =7
n(E) =2
SO the probability that there are 53 Thursdays in leap year is = n(E)/n(s) =2/7
Hope it helps you dear ☺️☺️
A leap year has 52 weeks and 2 days...
These 2 days can be:-
1) Sunday and Monday
2)Monday and Tuesday
3)Tuesday and Wednesday
4)Wednesday and Thursday
5)Thursday and Friday
6)Friday and Saturday
7)Saturday and Sunday
Therefore, n(S) =7
n(E) =2
SO the probability that there are 53 Thursdays in leap year is = n(E)/n(s) =2/7
Hope it helps you dear ☺️☺️
Anu726:
thank you
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