Math, asked by aadya20052, 1 year ago

What is the probability that a leap year selected at random will contain 53 Sundays?

Answers

Answered by chitranshsrivastava

the probability can be 1/7

chitranshsrivastava: ooops mine is wrong

chitranshsrivastava: so sorry

chitranshsrivastava: i have given the answer of non leap year

chitranshsrivastava: £££££ $●rr¥

Answered by subhamkmehta

The probability of a year being a leap year is 1/4 and being non-leap is 3/4.A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.So there are 7 possibiliyies out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is 2/7.

subhamkmehta: plz mark as brainiest

aadya20052: Thanks Shubham, this means a lot..Was working hard on this for hours..But couldn't figure it out

chitranshsrivastava: how

aadya20052: Ya sure

chitranshsrivastava: hi

chitranshsrivastava: its correct

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