What is the probability that a non Leap year has 53 Sundays
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Answered by
5
P (non leap year has 53 Sundays) =1/7
Ben11:
How 1/7
There are total 53 weeks in a normal year
sorry sorry 52 weeks
and 1 day is left still
so the probability that the remaining 1 day is Sunday is 1/7
as there are 7 days in a week
but only 1 day is sunday
mark my answer brainliest if u understood
Answered by
0
A leap year has 366 days and there are 52 complete weeks and two days more i.e., a leap year (366 days) = (52*7+2)days.
Total possible outcomes = 7
Now, favourable outcomes = [(Sunday, Monday) (Saturday, Sunday)] = 2
therefore, P(53 Sundays) = 2/7
Total possible outcomes = 7
Now, favourable outcomes = [(Sunday, Monday) (Saturday, Sunday)] = 2
therefore, P(53 Sundays) = 2/7
He has asked non leap year
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