Question

What is the probability that a number selected from 1 to 25 is a prime number ,when each of the given number is equally likely to be selected?

Answer 1

This is what I got. Hope it helps.

Answer 2

$Number \:of \: total \: possible \: outcomes \\= Numbers \: from \: 1 \: to \: 25 \\= 25 \: --(1)$

$Favourable \: outcomes \\= prime \: numbers \: from \: 1 \:to \: 25 \\= \{ 2,3,5,7,11,13,17,19,23 \}$

$Number \:of \: favourable\: outcomes = 9\:--(2)$

$Probability (prime ) = \frac{(2)}{(1)} \\= \frac{9}{25}$

Therefore.,

$\red{ Required \: probability } \green {= \frac{9}{25}}$

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