What is the probability that a number selected from natural numbers 1 to 25 is a prime number , when each of the given number is equally likely to be selected?
Answers
Answered by
0
Answer:
djdjsjevxjxossbwflfbebdkc
Answered by
0
Answer:
25/16
Step-by-step explanation:
Let E be the event of getting a not-a-prime number in the event of selecting from the numbers 1 to 25
Non-Prime numbers upto 25=1,4,6,8,9,10,12,14,15,16,18,20,21,22,24,25
No. of favorable outcomes=16
Total no. of possible outcomes =25
We know that, Probability P(E) =
(Total no.of possible outcomes) / (No.of favorable outcomes) = 25 / 16
Therefore, the probability that the drawn ticket bears a prime number is = 25/16
Hope this helped !
Similar questions