Question

What is the probability that a ordinary year has 53 Sundays?​

Answer 1

Answer:

So n(E) =1. Therefore the probability of a year having 53 Sundays = n(E)/n(S) = 1/7. If the year in question is a leap year, there are 366 days. Since 364 is a multiple of 7, there will be 52 Sundays, 52 Mondays,…………….

Answer 2

Answer:

hello buddy

Step-by-step explanation:

total no. of days in a year: 365

total no. of Sundays: 53

P( Sundays in an ordinary year)= 53/365.

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MARK AS BRAINLIEST