Question

What is the probability that a randomly chosen word has 3 consonants and 2 vowels from 6 consinants and 2 vowels when 5 letter word is formed

Answer 1

Answer:

Out of given 6 consonants & 3 vowels, words of 5 letters consisting of 2 consonants & 3 vowels are to be formed. Now selecting 2 consonants out of 6, no. of ways = C(6, 2) = (6!/2!×4! ) = 15 and selecting 3 vowels out of given 3 vowels, no. of ways = C(3, 3) = 1. Now these selected 5 letters words can be permuted among themselves in (5!) ways. Hence total no. of Possible words = 15 × 1 × (5!) = 15 × 120 = 1800 .

Note : Most of the words among these 1800 words may be meaningless