Question

What is the probability that a randomly thrown dart that hits the square board in shaded region.
(Take ???? = 22/7 and express in percentage)

Answer 1

Solution:-
radius of circle (r)= 2 cm
area of circle =
$\pi {r}^{2} \\ 3.14 \times 4 = 12.56 {cm}^{2}$
length of square = 2+2 = 4
area of square = 4×4 = 16
so drow od square board for dart
=> 16 - 12.56
=> 3.44
probability =
$\frac{3.44}{16} = 0.215$
HENCE , PROBABILITY OF RANDOMLY THROWN DART = 0.125

■I HOPE ITS HELP■

Answer 2

Hi ,

It is given that ,

i ) radius of the circle ( r ) = 2 cm

Area of the circle ( A1 ) = πr²

A1 = 22/7 × 2²

A1 = 88/7 square cm ----( 1 )

ii ) Side of the square( a ) = 2 × radius

a = 2 × 2 = 4 cm

Area of the Square ( A2 ) = a²

A2 = 4²

A2 = 16 square cm ---( 2 )


iii ) Area of the shaded region ( A ) = A2 - A1

A = 16 - 88/7

A = ( 112 - 88 )/7

A = 24/7 square cm ---( 3 )

Probability of hitting the

shaded region = ( favourable area )/total area


P( E ) = ( 3 )/( 2 )

= ( 22/7 )/( 16 )

= 24/( 7 × 16 )

= 3/14

As Percentage = 3/14 × 100%

= 300%/14

= 21.428 %

I hope this helps you.

: )