WHAT IS THE PROBABILITY THAT A TWO DIGIT NUMBER IS DIVISIBLE BY A)both 4 and 6 ,B)either 4or 6,but not both
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There are 90 two digit numbers(99–9). Out of this there are 6 numbers divisible by 15(15, 30, 45, 60, 75, 90), which are also divisible by 5. Therefore, the favorable cases are 30–6=24. Hence, the required probability is 24/90 = 4/15.
,B)either 4or 6,but not both
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