What is the probability that a two digit number selected at random will be a multiple of 2 not a multiple of 3
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Step-by-step explanation:
ANSWER ::
When a dice is rolled once the total number of possible outcomes = 6
Let A be the event that the the number on top will be
multiple of 2 not a multiple of 3
Then the points are = { 2, 4 }
Then total number of possible outcomes = 2
So the required probability = P(A) = 2/6 = 1/3
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