What is the probability that an ordinary year has 53 thusdays
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An year contains 365 days.
375/7= weeks+1 day
The 52 weeks conformly contains 52 Thursdays.
So,the probability of that remaining one day to Thursday is 1/7.
375/7= weeks+1 day
The 52 weeks conformly contains 52 Thursdays.
So,the probability of that remaining one day to Thursday is 1/7.
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