what is the probability that an ordinary year has 53 Sunday ?
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1/7 is the solution please follow if you liked the answer please add as brainliest
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Answer:
1/7
Step-by-step explanation:
see we have 365 days in a non-leap year.
52 weeks and one extra day= 365 days
52 weeks means definitely there are 52 Sundays (this is true for all other days also).
that means if the extra day comes out to be Sunday then we will have 53 Sundays.
so now the question boils down to what is the prob of this extra day to be a Sunday .
this extra one day can be
Monday or Tuesday or Wednesday or Thursday or Friday or Saturday or Sunday = sample space (s)
i.e n(s) = 7
so prob of this extra one day to be a Sunday is 1/7.
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