Math, asked by mohdzaid4999, 4 months ago

what is the probability that an ordinary year has 53 Sundays?​

Answers

Answered by arushi22saket
0

Answer:

In 365 days, Number of weeks = 52 weeks and 1 day is remaining. 1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.

Answered by SreyoshiChaudhuri
1

Answer:

Hi ! Let me help u with the answer.

Step-by-step explanation:

In 365 days, Number of weeks = 52 weeks and 1 day is remaining. 1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.

I Hope this answer helps you !!!

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