what is the probability that an ordinary year has 53 Sundays
Answers
Answered by
0
Step-by-step explanation:
Ordinary year contains 365 days
∴52 complete weeks and one day .
Possibilities for this one day are:
{Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday}
Total possibilities = 7
favorable cases = 1
∴ probability = 71
Option B is correct.
Answered by
0
Answer:
1/4
Step-by-step explanation:
only leap year has 53 sundays
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