Question

what is the probability that an ordinary year has 53 sundays ??​

Answer 1

Answer:

Step-by-step explanation:

Non-leap year = 365 days

In 365 days, Number of weeks = 52 weeks and 1 day is remaining.

For 52 weeks number of Sundays = 52

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Total of 7 outcomes, the favourable outcome is 1.

∴ probability of getting 53 Sundays = 1 / 7.

Answer 2

Required probability =1/7