Math, asked by siddhijain09875, 11 months ago

what is the probability that an ordinary year has (i) 53 Sundays (ii) Not a Sunday it is class 10 chapter​

Answers

Answered by anusha3579
2

Step-by-step explanation:

hey mate here is your :

ordinary year :

ordinary year has 365 days . there are 52 weeks in 365 days . 365 - 364 = 1 . 1 day will be left . the day may be Monday , Tuesday , Wednesday , Thursday , Friday , Saturday , Sunday . so the probability of getting 53 sundays in ordinary year = 1/7

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