Question

What is the probability that if a number is randomly chosen from 31 consecutive natural numbers it is divisible by 5

Answer 1

hope this is what u want...

Answer 2

Answer:

$\text{The probability is=}\frac{6}{31}$

Step-by-step explanation:

Given that  if a number is randomly chosen from 31 consecutive natural numbers. we have to find the probability that a number which is chosen is divisible by 5.

The sample space contains 1 to 31 consecutive natural numbers.

S={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31}

Let A be the set of numbers from above set S which is divisible by 5

A={5,10,15,20,25,30}

Hence, the probability that a number which is chosen from  S is divisible by 5 is

$\text{P(divisible by 5)=}\frac{n(A)}{n(S)}=\frac{6}{31}$