Math, asked by rochanaratakonda, 1 month ago

What is the probability that, if a number is randomly chosen from any 31 consecutive natural numbers. it is divisible by 5? (a) 6 / 31 (b) 7 / 31 (c) 6 / 31 or 7 / 31 (d) None of these​

Answers

Answered by llitzmisspaglill703
27

Answer:

Refer to attachment...

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Answered by studylover001
161

Answer:

αηsωεя :

The sample space is 31 consecutive natural numbers.

However, there are two cases,

1) When the first number is a multiple of 5: Here, there will be 7 numbers, divisible by 5 and so probability becomes 7/31

2) When the first number is not a multiple of 5 : In this case, there only are 6 multiples of 5 and 6

Hence, the probability becomes 31 So, the correct answer is option C.

Hope it helps you :)

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