What is the probability that, if a number is randomly chosen from any 31 consecutive natural numbers. it is divisible by 5? (a) 6 / 31 (b) 7 / 31 (c) 6 / 31 or 7 / 31 (d) None of these
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αηsωεя :
The sample space is 31 consecutive natural numbers.
However, there are two cases,
1) When the first number is a multiple of 5: Here, there will be 7 numbers, divisible by 5 and so probability becomes 7/31
2) When the first number is not a multiple of 5 : In this case, there only are 6 multiples of 5 and 6
Hence, the probability becomes 31 So, the correct answer is option C.
Hope it helps you :)
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