Question

What is the probability that, in six throws of a die, there will be exactly one each of "1""2" "3""4""5" and "6"

Answer 1

Answer:

Step-by-step explanation:

We know rhat p(e) =n(e)/n(s) so here n(e) is 1,2,3,4,5,6 and n(s) is 6so the answer is 1,2,3,4,5,6,/6