Question

what is the probability that leap year has 53 sundays​

Answer 1

Answer:

1/7

Step-by-step explanation:

In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday, Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.

Answer 2

$\maltese$ For leap year 366 days $\maltese$

Converting Days into Week....

366=(7*52)+2=364+2

So 52 weeks and remaining two days.

The two days may be

1. Sunday and Monday
2. Monday and Tuesday
3. Tuesday and Wednesday
4. Wednesday and Thursday
5. Thursday and Friday
6. Friday and Saturday
7. Saturday and Sunday

$\bigstar$ 2 Sundays are coming in the above possible outcomes $\bigstar$

Therefore the probability of 53 Sundays for Leap-year =  2/7

$\boxed{REQUIRED \;\; PROBABLITY\;\;= \;\;\frac{2}{7}}$