what is the probability that number card taken out is divisible by both 6and 8?
a) 4/25
b) 3/25
c) 2/25
d) 1/25
Answers
Answered by
0
Answer:
options are wrong according to me
there are 4 suits in a card system
each has 9 no cards
2 3 4 5 6 7 8 9 10
so there is no number divisible by both 6 and 8
Answered by
0
Answer:
the probability of choosing at random number that is divisible by from among 1 to 90 is equal to have the required probability equals to 23 divided 90 and the answer was not given in options.
Explanation:
I hope it's helpful to you
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