What is the probability that on any particular day the chickens will lay 4 eggs or less?
(i) 15 (ii) 37 (iii) 335 (iv) 17
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Given : The farmer recorded the laying habits of his chickens over a 10-week
E D
2 6
3 10
4 14
5 20
6 9
7 6
8 5
Total = 70
To Find : probability that on any particular day the chickens will lay 4 eggs or less
i) 1/5 (ii) 3/7 (iii) 3/35 (iv) 1/7
Solution
4 eggs or less = 2 , 3 or 4
= 6 + 10 + 14
= 30 Days
Probability that chickens will lay 4 eggs or less = 30/70 = 3/7
3/7 is the correct answer
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