What is the probability that shivam will not
be allowed to pick a marble from the bag?
Answers
Answer:
Step-by-step explanation:
Given : A game in a booth at a spring fair involves using a spinner first. Then, if the spinner stops on an even number, the player is allowed to pick a marble from a bag. The spinner and the marbles in the bag are represented in the diagram below.
To find : Different probabilities
Solution:
Number 1 , 2 , 4 , 6 , 8 , 10
n (Total numbers) = 6
n (Even numbers) = 5 ( 2 ,4 , 6 , 8 & 10)
Probability of Even number = 5/6
Total Marbles = 20
Black Marbles = 6
Probability of Black Marble = 6/20 = 3/10
Probability of Winning prize = (5/6) (3/10)
= 15/60
= 1/4
= 25 %
Probability of Winning prize = 25 %
probability that spinner stops on an even number = 5/6 ( very likely)
probability that spinner stops on a prime number = 1/6 not very likely
only prime number is 2
probability that spinner stops on cube of 2 ( 2³ = 8) = 1/6 not very likely
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