Math, asked by mgmarigold, 1 year ago

what is the probability that there are 53 sundays or 53 mondays in 1) A leap year 2) A non leap year

Answers

Answered by Nikki57
19
Hey!

______________

We know,

Number of days in a leap year = 366

Number of weeks in leap year = 366/7 = 52 weeks + 2 days

Two days possible sets are =>

1. Sunday and Monday
2. Monday and Tuesday
3. Tuesday and Wednesday
4. Wednesday and Thursday
5. Thursday and Friday
6. Friday and Saturday
7. Saturday and Sunday

Thus, probability of getting 53 Sundays and 53 Mondays = Probability that the other 2 days are Sunday and Monday

So, from the set, 1. Sunday and Monday is the only one that should happen so that the other two days are Sunday and Monday.

So, Probability = 1/7


______________

Hope it helps...!!!


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neosingh: its 'or' not 'and' so ans should be 3/7(case 7,1 &2) similarly for non leap year 2/7
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Answered by brainlyvirat187006
3

Answer:

Hey!

______________

We know,

Number of days in a leap year = 366

Number of weeks in leap year = 366/7 = 52 weeks + 2 days

Two days possible sets are =>

1. Sunday and Monday

2. Monday and Tuesday

3. Tuesday and Wednesday

4. Wednesday and Thursday

5. Thursday and Friday

6. Friday and Saturday

7. Saturday and Sunday

Thus, probability of getting 53 Sundays and 53 Mondays = Probability that the other 2 days are Sunday and Monday

So, from the set, 1. Sunday and Monday is the only one that should happen so that the other two days are Sunday and Monday.

So, Probability = 1/7

______________

Hope it helps...!!!

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