what is the probability that there are 53 sundays or 53 mondays in 1) A leap year 2) A non leap year
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Answered by
19
Hey!
______________
We know,
Number of days in a leap year = 366
Number of weeks in leap year = 366/7 = 52 weeks + 2 days
Two days possible sets are =>
1. Sunday and Monday
2. Monday and Tuesday
3. Tuesday and Wednesday
4. Wednesday and Thursday
5. Thursday and Friday
6. Friday and Saturday
7. Saturday and Sunday
Thus, probability of getting 53 Sundays and 53 Mondays = Probability that the other 2 days are Sunday and Monday
So, from the set, 1. Sunday and Monday is the only one that should happen so that the other two days are Sunday and Monday.
So, Probability = 1/7
______________
Hope it helps...!!!
______________
We know,
Number of days in a leap year = 366
Number of weeks in leap year = 366/7 = 52 weeks + 2 days
Two days possible sets are =>
1. Sunday and Monday
2. Monday and Tuesday
3. Tuesday and Wednesday
4. Wednesday and Thursday
5. Thursday and Friday
6. Friday and Saturday
7. Saturday and Sunday
Thus, probability of getting 53 Sundays and 53 Mondays = Probability that the other 2 days are Sunday and Monday
So, from the set, 1. Sunday and Monday is the only one that should happen so that the other two days are Sunday and Monday.
So, Probability = 1/7
______________
Hope it helps...!!!
Somyasisodiya:
all say that you are moderator
Answered by
3
Answer:
Hey!
______________
We know,
Number of days in a leap year = 366
Number of weeks in leap year = 366/7 = 52 weeks + 2 days
Two days possible sets are =>
1. Sunday and Monday
2. Monday and Tuesday
3. Tuesday and Wednesday
4. Wednesday and Thursday
5. Thursday and Friday
6. Friday and Saturday
7. Saturday and Sunday
Thus, probability of getting 53 Sundays and 53 Mondays = Probability that the other 2 days are Sunday and Monday
So, from the set, 1. Sunday and Monday is the only one that should happen so that the other two days are Sunday and Monday.
So, Probability = 1/7
______________
Hope it helps...!!!
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