What is the probability that two kings placed on a regular 8 x 8 chessboard, will be attacking each other given that no king is cornered or on the edge? (a king can attack any square adjacent to its position vertically, horizontally or diagonally).
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Answered by
0
Answer:
1/60
Step-by-step explanation:
it will be one is to sixty because 8*8=64-4as corner is substracted from the equation
Answered by
0
Answer:
1/14
Step-by-step explanation:
Number of boxes in a chess board = 64
As No King is cornered or on the edges, there are 4 edges so boxes to be subtracted are 8+7+7+6 = 28. these are total external boxes.
Boxes left with us = 64-28 = 36
1st king could be any where in these 36 boxes = 36/64
2nd king can now only be at 8 adjecent boxes to the 1st king = 8/63
Required Probability = 36/64*8/63= 1/14
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