What is the probability to have 53 sundays in a non leap year?
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Answered by
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We know that A non-leap year consists of 365 days.
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
Answered by
1
Since there are 52 complete weeks in a non leap year and 1 odd day
Therefore that 1 odd day can be Monday Tuesday Wednesday Thursday Friday Saturday and Sunday.
therefore total possible outcomes =7
number of favorable outcomes are 1
since probability = Number of favorable outcomes/Total number of outcomes
therefore Probability (53 Sundays in a non leap year)=1/7
Therefore that 1 odd day can be Monday Tuesday Wednesday Thursday Friday Saturday and Sunday.
therefore total possible outcomes =7
number of favorable outcomes are 1
since probability = Number of favorable outcomes/Total number of outcomes
therefore Probability (53 Sundays in a non leap year)=1/7
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