Question

What is the product formed when (CH3)3COC2H5+HI

Answer 1

Answer:

Explanation:

(CH3)3COC2H5+HI --------- (CH3)3CI + C2H5OH

Answer 2

When tert-butyl ethyl ether ( (CH$_{3}$)$_{3}$COC$_{2}$H$_{5}$ ) is treated with hydroiodic acid ( HI ) , the products formed are tert - butyl iodide ( (CH$_{3}$)$_{3}$C - I ) and ethyl alcohol ( C$_{2}$H$_{5}$OH ) .

The balanced chemical equation is -

(CH$_{3}$)$_{3}$COC$_{2}$H$_{5}$ + HI  →  (CH$_{3}$)$_{3}$C - I + C$_{2}$H$_{5}$OH

• Reaction proceeds by the SN1 mechanism .
• Iodide ion is added to three degree carbocation because it is most stable .