Question

what is the product of 23 and 79 to one place of accuracy?​

Answer 1

$Given \: numbers \: 23 \:and \:79$

/* First round the number 23 to one place of accuracy */

$Rounding \: 23 \: to \: one \:place \:of \\accuracy \:we \:get \: 20$

/* Since, 3 is less than 5 */

$Rounding \: 79 \: to \: one \:place \:of \\accuracy \:we \:get \: 80$

/* Since , 9 is greater than 5 */

$Required \:product = 20 \times 80 \\= 1600$

Therefore.,

$\red {The \:product \:of \:23 \:and\: 79 \:to}\\red{ one\: place \:of \:aaccuracy}\green { = 1600}$

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Answer 2

Answer:

2000

Step-by-step explanation:

The original product is 23*79 = 1817.

One place of accuracy means except the first one digit, the others will be 0. Before placing 1st digit you need to see the 2nd digit, if that is 5 or more you need to add 1 with the 1st digit.

Therefore, the result would be 2000 as the second digit is 7 (5 or more than 5), 1 being added with the first digit 1 = (1+1) = 2 and the remaining digits are o.

That's why the answer is 2000.